Pr(N = n) = 0 ,n=0,1,2,... n! 1 (x-m )2 Px(x) = 202 V2πσ2
Posted: Wed Dec 08, 2021 5:15 am
- 1 (4.64 KiB) Viewed 145 times
respectively.
Pr(N = n) = 0 ,n=0,1,2,... n!
1 (x-m )2 Px(x) = 202 V2πσ2
Show that the mean and variance of X are m and σ^2,
respectively.
Pr(N = n) = 0 ,n=0,1,2,... n!
1 (x-m )2 Px(x) = 202 V2πσ2