- Trydint Bubble Gum Company Claims That 3 Out Of 10 People Prefer Their Gum To Eklypse Test Their Claim At The 95 Co 1 (149.13 KiB) Viewed 117 times
"Trydint" bubble-gum company claims that 3 out of 10 people prefer their gum to "Eklypse". Test their claim at the 95 confidence level. The null and alternative hypothesis in symbols would be: O Ho:P < 0.3 H:p > 0.3 OH:p > 0.3 H
< 0.3 OH:u= 0.3 H, :μ + 0.3 Ο Ηο:μ Σ 0.3 H, :μ<0.3 Ο Ηο:μ < 0.3 H1 :μ > 0.3 OH:p=0.3 H:P + 0.3 The null hypothesis in words would be: The proportion of people in a sample that prefer Trydint gum is not 0.3 The proportion of all people that prefer Trydint gum is 0.3 The average of people that prefer Trydint gum is not 0.3. The proportion of all people that prefer Trydint gum is less than 0.3. The proportion of people in a sample that prefers Trydint gum is 0.3. The average of people that prefer Trydint gum is 0.3. The proportion of all people that prefer Trydint gum is greater than 0.3. Based on a sample of 150 people, 32 said they prefer "Trydint" gum to "Eklypse". The point estimate is: (to 3 decimals) The 95 % confidence interval is: to (to 3 decimals) Based on this we: Reject the null hypothesis O Fail to reject the null hypothesis
A well-known brokerage firm executive claimed that 60% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 400 people, 66% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is larger than 60% at the 0.05 significance level. The null and alternative hypothesis would be: Ho:p = 0.6 Ho:P < 0.6 Hoiu > 0.6 Ho:u= 0.6 Ho:u < 0.6 Ho:p> 0.6 H:P + 0.6 H :p > 0.6 H1:4 < 0.6 H1:41 + 0.6 H1:4 > 0.6 H1:p < 0.6 The test is: right-tailed two-tailed left-tailed The test statistic is: (to 3 decimals) The p-value is: (to 4 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
You are conducting a study to see if the proportion of men over 50 who regularly have their prostate examined is significantly more than 0.39. You use a significance level of a = 0.01. Ho:p = 0.39 H:p > 0.39 You obtain a sample of size n = 708 in which there are 312 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... Oreject the null O accept the null O fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their prostate examined is more than 0.39. There is not sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their prostate examined is more than 0.39. The sample data support the claim that the proportion of men over 50 who regularly have their prostate examined is more than 0.39. There is not sufficient sample evidence to support the claim that the proportion of men over 50 who regularly have their prostate examined is more than 0.39.