L1=120 L2=160 L3=120 F(kN)=-11.6 Mf(kN*m)=13.91 g(kN/m)=18.4 and calculation.
Posted: Fri Jun 10, 2022 11:29 am
L1=120
L2=160
L3=120
F(kN)=-11.6
Mf(kN*m)=13.91
g(kN/m)=18.4
and calculation.
(12) F £7 Tun 러
You need to do: 1) diagrams of axial forces, torsional moments, shearing forces and bending moments (on same page with initial schema) (8 points) 2) and design one of the three rods only. (2 points)
L2=160
L3=120
F(kN)=-11.6
Mf(kN*m)=13.91
g(kN/m)=18.4
- L1 120 L2 160 L3 120 F Kn 11 6 Mf Kn M 13 91 G Kn M 18 4 And Calculation 1 (22.18 KiB) Viewed 111 times
- L1 120 L2 160 L3 120 F Kn 11 6 Mf Kn M 13 91 G Kn M 18 4 And Calculation 2 (9.03 KiB) Viewed 111 times
(12) F £7 Tun 러
You need to do: 1) diagrams of axial forces, torsional moments, shearing forces and bending moments (on same page with initial schema) (8 points) 2) and design one of the three rods only. (2 points)