L1=120 L2=160 L3=120 F(kN)=-11.6 Mf(kN*m)=13.91 g(kN/m)=18.4 and calculation.

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correctanswer
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L1=120 L2=160 L3=120 F(kN)=-11.6 Mf(kN*m)=13.91 g(kN/m)=18.4 and calculation.

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L1=120
L2=160
L3=120
F(kN)=-11.6
Mf(kN*m)=13.91
g(kN/m)=18.4
L1 120 L2 160 L3 120 F Kn 11 6 Mf Kn M 13 91 G Kn M 18 4 And Calculation 1
L1 120 L2 160 L3 120 F Kn 11 6 Mf Kn M 13 91 G Kn M 18 4 And Calculation 1 (22.18 KiB) Viewed 108 times
L1 120 L2 160 L3 120 F Kn 11 6 Mf Kn M 13 91 G Kn M 18 4 And Calculation 2
L1 120 L2 160 L3 120 F Kn 11 6 Mf Kn M 13 91 G Kn M 18 4 And Calculation 2 (9.03 KiB) Viewed 108 times
and calculation.
(12) F £7 Tun 러
You need to do: 1) diagrams of axial forces, torsional moments, shearing forces and bending moments (on same page with initial schema) (8 points) 2) and design one of the three rods only. (2 points)
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