Another Example: 0.150px Calculate Keq for A+2B C +3D given that 0.300 mol A and 0.200 mol B are placed in a 1.00 L cont

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correctanswer
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Another Example: 0.150px Calculate Keq for A+2B C +3D given that 0.300 mol A and 0.200 mol B are placed in a 1.00 L cont

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Another Example 0 150px Calculate Keq For A 2b C 3d Given That 0 300 Mol A And 0 200 Mol B Are Placed In A 1 00 L Cont 1
Another Example 0 150px Calculate Keq For A 2b C 3d Given That 0 300 Mol A And 0 200 Mol B Are Placed In A 1 00 L Cont 1 (483.85 KiB) Viewed 109 times
I dont know how the values for the c in the table were found, a
step by step explanation would be appreciated, thank you!!!
Another Example: 0.150px Calculate Keq for A+2B C +3D given that 0.300 mol A and 0.200 mol B are placed in a 1.00 L container. At equilibrium [D]=0.150 M A + 2B = C 1 3D I 0.300 0.200 0 0 C-0.0500 0.100 + 0.0500 + 0.150 = 0. 0.150 3 [C] []³ [A] a (0.0500) (0.150) (0.250) (0.100)² - [products] [reactants] Keg= = 0.0675
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