In the redox reaction: Cr₂O72(aq) + 6S₂032(aq) + 14H*(aq) → 2Cr³+ (aq) +354062(aq) + 7H₂O(l) - S₂032 is reduced and H* i

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
correctanswer
Posts: 43759
Joined: Sat Aug 07, 2021 7:38 am

In the redox reaction: Cr₂O72(aq) + 6S₂032(aq) + 14H*(aq) → 2Cr³+ (aq) +354062(aq) + 7H₂O(l) - S₂032 is reduced and H* i

Post by correctanswer »

In The Redox Reaction Cr O72 Aq 6s 032 Aq 14h Aq 2cr Aq 354062 Aq 7h O L S 032 Is Reduced And H I 1
In The Redox Reaction Cr O72 Aq 6s 032 Aq 14h Aq 2cr Aq 354062 Aq 7h O L S 032 Is Reduced And H I 1 (41.53 KiB) Viewed 66 times
In the redox reaction: Cr₂O72(aq) + 6S₂032(aq) + 14H*(aq) → 2Cr³+ (aq) +354062(aq) + 7H₂O(l) - S₂032 is reduced and H* is oxidized. O Cr₂O72 is oxidized and S₂O3²- is reduced. O Cr₂0₂2 is oxidized and H* is reduced. O Cr₂O72- is reduced and S₂O3²- is oxidized.
Register for solutions, replies, and use board search function. Answer Happy Forum is an archive of questions covering all technical subjects across the Internet.
Top
Post Reply

Return to “Archived Questions & Answers”