19. If 3.90+10³5 of energy is Container of liquia Supplied to a oxygen at oxygen can evaporate LU = 2.1×105 J/kg 2 f = 1

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19. If 3.90+10³5 of energy is Container of liquia Supplied to a oxygen at oxygen can evaporate LU = 2.1×105 J/kg 2 f = 1

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19 If 3 90 10 5 Of Energy Is Container Of Liquia Supplied To A Oxygen At Oxygen Can Evaporate Lu 2 1 105 J Kg 2 F 1 1
19 If 3 90 10 5 Of Energy Is Container Of Liquia Supplied To A Oxygen At Oxygen Can Evaporate Lu 2 1 105 J Kg 2 F 1 1 (27.18 KiB) Viewed 278 times
19. If 3.90+10³5 of energy is Container of liquia Supplied to a oxygen at oxygen can evaporate LU = 2.1×105 J/kg 2 f = 1.4x 104 J/kg Boiling point = 90k G) 1.86 kg 6)27-8619 () 0.54 105 d) 2.241c9- -183 %℃, how much + h
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