Q1(9pts) For the STTL circuit shown for BJTS VBE(FA)-0.7V, VBE(SAT)-0.8V and VCE(SAT) 0.1V. For the SBJT, VBE(FA)-0.7V,

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answerhappygod
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Q1(9pts) For the STTL circuit shown for BJTS VBE(FA)-0.7V, VBE(SAT)-0.8V and VCE(SAT) 0.1V. For the SBJT, VBE(FA)-0.7V,

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Q1 9pts For The Sttl Circuit Shown For Bjts Vbe Fa 0 7v Vbe Sat 0 8v And Vce Sat 0 1v For The Sbjt Vbe Fa 0 7v 1
Q1 9pts For The Sttl Circuit Shown For Bjts Vbe Fa 0 7v Vbe Sat 0 8v And Vce Sat 0 1v For The Sbjt Vbe Fa 0 7v 1 (29.77 KiB) Viewed 129 times
Q1(9pts) For the STTL circuit shown for BJTS VBE(FA)-0.7V, VBE(SAT)-0.8V and VCE(SAT) 0.1V. For the SBJT, VBE(FA)-0.7V, VBE(Hard)-0.7V and VCE(Hard)-0.4V. And VSBD-0.3V. Given that two loads are connected to the output of the driver, and that driver and loads are identical, find the following given that VIN is at logic high: IOL= 2.5V 2.5V In.'= Ki DI' 14 IRD = 0.1 mA IES= IRB= IRC= Re 0.7K VouT 0.2 MA 3 Vour Ro 0.7K Another identical gate at load
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