(a) what is mfp of 0,0253eV neutrons in Zr? For Zr: A= 55.b, p=6.5g/cm^2 , σs=8b, σa=0.18b (b)To a first approximation,

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answerhappygod
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(a) what is mfp of 0,0253eV neutrons in Zr? For Zr: A= 55.b, p=6.5g/cm^2 , σs=8b, σa=0.18b (b)To a first approximation,

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(a) what is mfp of 0,0253eV neutrons in Zr? For Zr: A= 55.b, p=6.5g/cm^2 , σs=8b, σa=0.18b
(b)To a first approximation, what is the probability that such a neutron will interact as it goes through a 2-mm thick Zr wall?(in %)
(c)what is the probability that the neutron will be absorbed?(in %)
Please solve c
please use the unit written in the question
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