- The Electrophilic Aromatic Substitution Of Isopropylbenzene With Bra And Febrz Gives 1 Bromo 4 Isopropylbenzene Br B 1 (109.08 KiB) Viewed 135 times
- The Electrophilic Aromatic Substitution Of Isopropylbenzene With Bra And Febrz Gives 1 Bromo 4 Isopropylbenzene Br B 2 (103.23 KiB) Viewed 135 times
You have not correctly completed step 3.
Did you re‑draw the FeBr5FeBr5 from step 2 with both
charges and all the lone pairs on the bromines?
Draw one curved arrow from the alkylbenzene. Note that bromine
is in the para position in the product. Which
bromine is attacked? Draw a second curved arrow to break the bond
connected to the bromine that is attacked.
Check that all lone pairs of electrons and formal charges
are included.
The electrophilic aromatic substitution of isopropylbenzene with Brą and FeBrz gives 1-bromo-4-isopropylbenzene. :Br: :Br: HBr Product of bromine and FeBrz sos FeBrz :Br Complete the curved-arrow mechanism, beginning with formation of the active brominating reagent. Remember to include lone pairs and formal charges where appropriate. Step 1: Draw one or more curved arrows to form the product of Br, and FeBrz. Step 2: Draw the product of Br, and FeBrz. : Br : : Br : Fe : Br Br : : Br :
For the final two steps of the mechanism, include nonbonding electrons, charges, and curved arrows. Draw curved arrows and the structure for the simple "alkene" addition product; omit delocalization/resonance contributors. and FeBrz and Step 3: Redraw the product of Brz proceed with the mechanism. Step 4: Draw the resulting organic and inorganic species, and then complete the mechanism. : Br : Br : Br : H Br Fe Br al | Br Incorrect Incorrect