METABOLIC BIOCHEMISTRY PLEASE HELP ASAP
Question 14 2 pts This is a two part question. The change in enthalpy and entropy for a certain reaction are 2 kJ/mol and 12 J/K.mol, respectively. The equilibrium constant Keq for this reaction is 1.89. Using the equations below, answer the following two questions. AGⓇ =AHⓇ - TASⓇ, AGⓇ-RT ln Keq, = In Keq ΔΗΘ Ase + RT R https://canvas.uts.edu.au/assessment questions/356938/files/1562667/download? verifier=UVvzUkTwCFsZaxco9vbiBpuQSf3uYbNE5nvGotPC The value for the Universal gas constant is 8.315 J/mol.K. A) Assuming standard conditions, calculate the free energy (AG) for the reaction. You do not need to show your workings but don't forget your units. B) If the temperate was increased to 37 deg C, would the reaction become more or less favorable. Justify your answer Edit View Insert Format Tools Table
METABOLIC BIOCHEMISTRY PLEASE HELP ASAP
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