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4. Given the data: 4NH3(g) + 302(g) 0 2N2(g) + 6H2O(1), AH = -1530kJmol-¹ H2(g) + 1/2O2(g) □ H₂O(1), AH = -288 kJmol-¹ C

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4. Given the data: 4NH3(g) + 302(g) 0 2N2(g) + 6H2O(1), AH = -1530kJmol-¹ H2(g) + 1/2O2(g) □ H₂O(1), AH = -288 kJmol-¹ C

Posted: Thu Jun 09, 2022 9:51 am
by answerhappygod
4 Given The Data 4nh3 G 302 G 0 2n2 G 6h2o 1 Ah 1530kjmol H2 G 1 2o2 G H O 1 Ah 288 Kjmol C 1
4 Given The Data 4nh3 G 302 G 0 2n2 G 6h2o 1 Ah 1530kjmol H2 G 1 2o2 G H O 1 Ah 288 Kjmol C 1 (13.11 KiB) Viewed 48 times
4. Given the data: 4NH3(g) + 302(g) 0 2N2(g) + 6H2O(1), AH = -1530kJmol-¹ H2(g) + 1/2O2(g) □ H₂O(1), AH = -288 kJmol-¹ Construct an enthalpy cycle and calculate the enthalpy of formation of ammonia.
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