4. Given the data: 4NH3(g) + 302(g) 0 2N2(g) + 6H2O(1), AH = -1530kJmol-¹ H2(g) + 1/2O2(g) □ H₂O(1), AH = -288 kJmol-¹ C

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

4. Given the data: 4NH3(g) + 302(g) 0 2N2(g) + 6H2O(1), AH = -1530kJmol-¹ H2(g) + 1/2O2(g) □ H₂O(1), AH = -288 kJmol-¹ C

Post by answerhappygod »

4 Given The Data 4nh3 G 302 G 0 2n2 G 6h2o 1 Ah 1530kjmol H2 G 1 2o2 G H O 1 Ah 288 Kjmol C 1
4 Given The Data 4nh3 G 302 G 0 2n2 G 6h2o 1 Ah 1530kjmol H2 G 1 2o2 G H O 1 Ah 288 Kjmol C 1 (13.11 KiB) Viewed 46 times
4. Given the data: 4NH3(g) + 302(g) 0 2N2(g) + 6H2O(1), AH = -1530kJmol-¹ H2(g) + 1/2O2(g) □ H₂O(1), AH = -288 kJmol-¹ Construct an enthalpy cycle and calculate the enthalpy of formation of ammonia.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Top
Post Reply

Return to “Archived Questions & Answers”