1 (4 points) Draw the resonance structures for the following species. If no resonance structures are present, state so.

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

1 (4 points) Draw the resonance structures for the following species. If no resonance structures are present, state so.

Post by answerhappygod »

1 4 Points Draw The Resonance Structures For The Following Species If No Resonance Structures Are Present State So 1
1 4 Points Draw The Resonance Structures For The Following Species If No Resonance Structures Are Present State So 1 (56.31 KiB) Viewed 108 times
1 (4 points) Draw the resonance structures for the following species. If no resonance structures are present, state so. Show all non-zero formal charges, all lone pairs and multiple bonds (if present). Label the structures as major, minor, or equivalent. a CH3-CH2-CH=CH-CH₂¹- b [CH3CH₂C(O)C(CH3)C(O)CH₂CH3]¹-

3 (3 points) Draw the most stable conformation for cis-1-isopropyl-2-methylcyclohexane and for trans-1-isopropyl-2-methylcyclohexane. Circle the compound that is more stable. Justify your answer. I I A I cis-1-isopropyl-2-methylcyclohexane trans-1-isopropyl-2-methylcyclohexane

1 (3 points) Write a detailed mechanism for the following reaction. Label the initiation, propagation, and termination steps clearly. light (CH3)3CH + Br2 (CH3)3CBr + HBr

2 (3 points) For the following reaction, when the [CH30¹] is doubled and the [(CH3)3CCl] is tripled, the initial rate of the reaction triples. Determine the rate law. Circle the correct answer. (CH3)3CC1 + CH30¹ → (CH3)3COCH3 + C₁¹- A rate = e = kr[CH30¹] B rate = kr[(CH3)3CC1] C rate = kr[(CH3)3CCI][CH30¹] D rate = kr[(CH3)3CCI] [CH30¹1³ E rate = k₁[(CH3)3CC1]³[CH30¹-₁² 3 (2 points) Label each of the hydrogen atoms in the following compound as 1º, 2º, or 3°. You may need to expand the structure. Include the hydrogen atoms attached to the ring carbon atoms. CH3-CH2 CH3-CH H3C
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply