- Ml Setation X 1 L Solution 100 Ml Solution 155 Starting Amount 155 Ml Solution X Lsolution Ml Selation 1 100 0 762 Mol F 1 (233.56 KiB) Viewed 35 times
mL setation X 1 L solution 100 mL solution 155 STARTING AMOUNT 155 mL solution x Lsolution ml-selation 1 100 0.762 mol FeCl₂ 1 L solution If you have 155 mL solution of a 0.762 M FeCl solution, how many grams of FeCl, are contained in this sample? 0.762 molFECT 162.2 g FeCl, X 1 selation 1 molFECT = 19.2 g FeCl, RESET 5 100 7.28 x 10* 0.01 1.92 0.118 1 35.45 L solution mol FeCl, mL solution 25.1 155 g Cl X 162.2 g FeCl, 1 mol FeCl ADD FACTOR 1000 19.2 g Fe DELETE A 0.203 162.2 55.85 4.92 6.60 0.762 mol FeCl/L solution ANSWER 0.1 12.6 124 M FeCl₂ g FeCl₂ g FeCl/mol FeCl, 19.2 g FeCl, +