25.0 mL of 0.51 mol/L Na3PO,(aq) Titrated with 0.50 mol/L HCl(aq) P Q R S 0 10 20 30 40 50 60 70 80 90 100 Volume of HCI

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answerhappygod
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25.0 mL of 0.51 mol/L Na3PO,(aq) Titrated with 0.50 mol/L HCl(aq) P Q R S 0 10 20 30 40 50 60 70 80 90 100 Volume of HCI

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25 0 Ml Of 0 51 Mol L Na3po Aq Titrated With 0 50 Mol L Hcl Aq P Q R S 0 10 20 30 40 50 60 70 80 90 100 Volume Of Hci 1
25 0 Ml Of 0 51 Mol L Na3po Aq Titrated With 0 50 Mol L Hcl Aq P Q R S 0 10 20 30 40 50 60 70 80 90 100 Volume Of Hci 1 (124.75 KiB) Viewed 35 times
hii please help with this question asap!
25 0 Ml Of 0 51 Mol L Na3po Aq Titrated With 0 50 Mol L Hcl Aq P Q R S 0 10 20 30 40 50 60 70 80 90 100 Volume Of Hci 2
25 0 Ml Of 0 51 Mol L Na3po Aq Titrated With 0 50 Mol L Hcl Aq P Q R S 0 10 20 30 40 50 60 70 80 90 100 Volume Of Hci 2 (332.72 KiB) Viewed 35 times
25.0 mL of 0.51 mol/L Na3PO,(aq) Titrated with 0.50 mol/L HCl(aq) P Q R S 0 10 20 30 40 50 60 70 80 90 100 Volume of HCI (mL) The equation for the reaction that is completed at point Q is OH3O+ (aq) + HPO42 (aq) → H₂O (1) + H₂PO4 (aq) 3- O2H3O*(aq) + PO4³ (aq) → 2H₂O (1) + HPO4² (aq) OH30* (aq) + PO43 (aq) → H₂O (1) + HPO4²- (aq) 2H3O+ (aq) + PO4³-(aq) → 2H₂O (1) + H₂PO4 (aq) PH 14 12 10 8 6 4 2 0 1

21. The entities present that are responsible for the shape of the curve at section P of the above graph are OHPO42-(aq) and H3O+ (aq) PO4³-(aq) and H₂O*(aq) O PO4³-(aq) and HPO4² (aq) O HPO42 (aq) and H₂PO4 (aq)
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