11. (15 pts.) The square below is 5.20 mm on each side, has current I₁ of 5.0 A coming out of the page at the upper left

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answerhappygod
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11. (15 pts.) The square below is 5.20 mm on each side, has current I₁ of 5.0 A coming out of the page at the upper left

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11 15 Pts The Square Below Is 5 20 Mm On Each Side Has Current I Of 5 0 A Coming Out Of The Page At The Upper Left 1
11 15 Pts The Square Below Is 5 20 Mm On Each Side Has Current I Of 5 0 A Coming Out Of The Page At The Upper Left 1 (163.82 KiB) Viewed 28 times
11. (15 pts.) The square below is 5.20 mm on each side, has current I₁ of 5.0 A coming out of the page at the upper left corner, and current I₂ of 2.0 A going into the page at the upper right corner. dT 12 b a. Draw in the directions of the magnetic fields at point P from each individual current. (2 pts.) Not the Correct directions. b. What is the magnitude of the net + 2 magnetic field at point P? (5 pts.) F = _PoI₁ + = ܕ ܂ 5.20mm Bídicos B₂ d I₁ : 5.0 A 1₂: 2.0A 27(520) 0.0010264389 (7.0) Can't just add 0.007185 N like this. c. What is the direction of the net magnetic field at point P? (Be sure to specify where +the angle is measured relative to.) (3 pts.) B₁ Pointing up. P Have to vector components. use d. Draw an Amperian loop in the above diagram that would have a total path integral of +(B-dl= (Ho 3.0 A) around it. (5 pts.) Loop on diagram? * SB.dl = (P. - 3.0 A) . 'I enclosed path ать 6-7 d d-7.c c-79 520 m Po I₂ 27 (520m) (I₁+I₂) 27(520m) Po Σπ(520m) = (47X10") B₂ ·(5.0+ 2.0)
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