0₁ Incident beam 60° 0₂ 60° n = 1.65 60⁰ Note: Figure not drawn to scale. A beam of light passes from air to glass to ai

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0 Incident Beam 60 0 60 N 1 65 60 Note Figure Not Drawn To Scale A Beam Of Light Passes From Air To Glass To Ai 1 (127.61 KiB) Viewed 40 times

0₁ Incident beam 60° 0₂ 60° n = 1.65 60⁰ Note: Figure not drawn to scale. A beam of light passes from air to glass to air as shown above through a triangular piece of glass. The index of refraction of the glass is 1.65 and the incident beam is noted in the diagram above. 1. Suppose 0₁ = 55°. Calculate 02. 2. Identify the relationship between 03 and 04 by labeling one of them incident and the other refracted. Calculate 04. 3. Calculate the critical angle for light passing from glass to air. Use the provided value for glass index of refraction. 4. Using the diagram above, calculate the initial incident angle required to produce total internal reflection at the second surface. 0₂