An alpha particle with kinetic energy 13.0 MeV makes a collision with lead nucleus, but it is not "aimed" at the center

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An alpha particle with kinetic energy 13.0 MeV makes a collision with lead nucleus, but it is not "aimed" at the center

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An Alpha Particle With Kinetic Energy 13 0 Mev Makes A Collision With Lead Nucleus But It Is Not Aimed At The Center 1
An Alpha Particle With Kinetic Energy 13 0 Mev Makes A Collision With Lead Nucleus But It Is Not Aimed At The Center 1 (82.15 KiB) Viewed 18 times
An Alpha Particle With Kinetic Energy 13 0 Mev Makes A Collision With Lead Nucleus But It Is Not Aimed At The Center 2
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An Alpha Particle With Kinetic Energy 13 0 Mev Makes A Collision With Lead Nucleus But It Is Not Aimed At The Center 3
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An alpha particle with kinetic energy 13.0 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L= pob, where po is the magnitude of the initial momentum of the alpha particle and b=1.00×10-12 m. (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.)

▾ Part A What is the distance of closest approach? 15. ΑΣΦ ▼ T = Submit Request Answer Part B Repeat for b=1.00×10-13 m. ] ? m

Part C Repeat for b=1.40×10-14 m 17 ΑΣΦ = 99999 ] ? m
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