- Wnet Kf Ki 1 Mv Ugrav Mgh K U Wnc K Uf Block A Moving To The Left At 3 5 M S Slides Up A Frictio 1 (172.76 KiB) Viewed 24 times
Wnet = Kf - Ki, 1 =mv², Ugrav = mgh, K₁ + U₁ + WNC = K₁ + Uf Block A, moving to the left at 3.5 m/s, slides up a frictionless inclined ramp. You observe that block A comes to a stop at a height H above the ground. d = 0.50 m 3.5 m/s a. If the angle of inclination of the ramp was smaller, would that cause the maximum height of block A to be larger than, the same as or smaller than height H? Select one. A mA = 4.0 kg b. Now assume that the inclined ramp has friction. Block A initially slides up the ramp, comes to a stop and then slides back down the ramp. When block A is back on the horizontal surface, will its speed be larger than, the same as or smaller than 3.5 m/s? Briefly expain. c. Now assume that the floor is frictionless, but the ramp has friction. The magnitude of the frictional force between the block and the ramp is fk = 12.0 N. Block A travels a distance d = 0.50 m up the ramp, before coming to a stop. At what height above the ground will block A stop? i. 0.382 m ii. 0.472 m iii. 0.625 m iv. 0.778 m v. 0.931 m K= WF Fdcos0F-d fk = µk * n