5. DATA 1 (mA) emf (mv) 4 14.2 5 17.5 6 21.1 7 24.8 8 28.6 9 32.5 10 36.2 The equation of the line is a straight-line e

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answerhappygod
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5. DATA 1 (mA) emf (mv) 4 14.2 5 17.5 6 21.1 7 24.8 8 28.6 9 32.5 10 36.2 The equation of the line is a straight-line e

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5 Data 1 Ma Emf Mv 4 14 2 5 17 5 6 21 1 7 24 8 8 28 6 9 32 5 10 36 2 The Equation Of The Line Is A Straight Line E 1
5 Data 1 Ma Emf Mv 4 14 2 5 17 5 6 21 1 7 24 8 8 28 6 9 32 5 10 36 2 The Equation Of The Line Is A Straight Line E 1 (5.07 KiB) Viewed 28 times
5. DATA 1 (mA) emf (mv) 4 14.2 5 17.5 6 21.1 7 24.8 8 28.6 9 32.5 10 36.2

The equation of the line is a straight-line equation from which you can read the slope of the line easily. (Slope is the coefficient of x) emf (mv) vs I (mA) 40 35 y=3.6714x-0.7476... 30 25 20 15 10 5 0 6 8 10 7. CALCULATIONS Ø = 20 mm m₁ = 476 Wdg/m n₂ = 300 Wdg f = 10.7 kHz = 10.7 x 10³ Hz H40,theoretical = 47 × 10-7 N/A² ≈ 1.26 x 10-6 N/A² 2 st 4 12 Calculate the cross-sectional area of the induction coil: A = πr² = π ( × 10-³) ²= Write down the slope of the line: slope = [emf] = Using the relation emƒ = µAn₁n₂(2у)1, calculate the experimental value for vacuum permeability: slope 10,experimental An₁n₂ (2nf) Calculate the error percentage: Mo,theoretical - Ho,experimental error % = x 100% = Ho,theoretical
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