In this question you may use the fact that under normal conditions a monatomic ideal gas has three degrees of freedom an

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In this question you may use the fact that under normal conditions a monatomic ideal gas has three degrees of freedom an

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In This Question You May Use The Fact That Under Normal Conditions A Monatomic Ideal Gas Has Three Degrees Of Freedom An 1
In This Question You May Use The Fact That Under Normal Conditions A Monatomic Ideal Gas Has Three Degrees Of Freedom An 1 (58.3 KiB) Viewed 30 times
In this question you may use the fact that under normal conditions a monatomic ideal gas has three degrees of freedom and a diatomic gas has five degrees of freedom. A sample of 2.00 x 10-¹ moles of a diatomic ideal gas is contained in a cylinder whose volume can be changed by moving a piston as shown in Figure 2. The gas initially has a volume of 4.00 x 10-³ m³ and a temperature of 2.95 x 10² K. V4.00 x 10-3 m³ Figure 2 For use in Question 14 (a) The inner face of the piston has an area of 1.00×10-² m². Calculate the magnitude of the perpendicular force exerted on this face of the piston by the gas in the initial state. (b) The gas is now compressed isothermally by moving the piston, reducing its volume by a factor of 2.00. (i) What is the change in internal energy of the gas? (ii) Calculate the change in entropy of the gas as a result of the isothermal compression. (iii) Calculate the amount of heat transferred to or from the gas during the compression. (iv) How much work is done by the piston on the gas during the compression? (c) The cylinder is then isolated from its surroundings and the piston moved again, expanding the gas adiabatically back to its original volume, i.e. the gas expands adiabatically by a factor of 2.00. (i) What is the change in entropy of the gas during this expansion? (ii) Calculate the final temperature of the gas after the expansion. (d) The process is now repeated using a sample of 2.00 x 10-¹ moles of a monatomic ideal gas, starting from the same initial volume of 4.00 x 10 m³ and temperature of 2.95 x 10² K. The system is again compressed isothermally by a factor of 2.00 followed by an adiabatic expansion to the original volume. Calculate the new final temperature of the gas. 3 [1] [4] [2] [1] [1] [4] [3]
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