5. A gas mixture containing 15 mole% A and 85 mole% inerts is fed to an absorption tower where it is contacted with liqu

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5 A Gas Mixture Containing 15 Mole A And 85 Mole Inerts Is Fed To An Absorption Tower Where It Is Contacted With Liqu 1 (47.63 KiB) Viewed 28 times

5. A gas mixture containing 15 mole% A and 85 mole% inerts is fed to an absorption tower where it is contacted with liquid solvent B which absorbs A. The mole ratio of solvent to gas entering tower is 2: 1. The gas leaving the absorber contains 2.5% A, 1.5% B and rest inerts on mole basis. Calculate: (i) The percentage recovery of solute 'A' and (ii) The fraction of solvent 'B' fed to column lost in gas leaving the tower. During the process, some solvent evaporates and gets added in gas leaving the tower. Solvent B=? Gas leaving A = 2.5% B = 1,5% /= 96% Feed gas A = 15% 1=85% Absorption tower B = Solvent A = Solute