At -31.2C Po propane = 1200 mmHg while Po n-butane = 200 mmHg. a) calculate the mole fraction of propane in the liquid m
Posted: Wed Jun 08, 2022 8:58 am
At -31.2C Po propane = 1200 mmHg while Po n-butane = 200 mmHg.
a) calculate the mole fraction of propane in the liquid mixture that boils at -31.2C
under pressure 760 mmHg
b) Calculate the mole fraction of propane in the vapor phase in equilibrium with the liquid in (a)
a) calculate the mole fraction of propane in the liquid mixture that boils at -31.2C
under pressure 760 mmHg
b) Calculate the mole fraction of propane in the vapor phase in equilibrium with the liquid in (a)