At -31.2C Po propane = 1200 mmHg while Po n-butane = 200 mmHg. a) calculate the mole fraction of propane in the liquid m

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answerhappygod
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At -31.2C Po propane = 1200 mmHg while Po n-butane = 200 mmHg. a) calculate the mole fraction of propane in the liquid m

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At -31.2C Po propane = 1200 mmHg while Po n-butane = 200 mmHg.
a) calculate the mole fraction of propane in the liquid mixture that boils at -31.2C
under pressure 760 mmHg
b) Calculate the mole fraction of propane in the vapor phase in equilibrium with the liquid in (a)
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