Intersection angle: 30
- Radius 150m Intersection Angle 30 1 (34.62 KiB) Viewed 33 times
Radius :150m Intersection angle: 30
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answerhappygod
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Radius :150m Intersection angle: 30
Radius :150m
Intersection angle: 30
[40 pts] For the horizontal curve and the original cross-section of a two lane highway shown below, the following data is given: PI - Radius (R) = 15# m T T Intersection angle (A) = Design Speed (Va) = 60 km/h Stopping Sight Distance (S.) = 72.$$ m PC PT OE î Sr = 1/200 - f = 0.15 IE 2% 2% IE OE Find; a) Minimum lateral clearance distance (M.) b) Determine the maximum superelevation (emax) and transition length (L.) for rotation around centerline. c) Draw superelevation diagram by rotating the roadway around the center line and show all necessary cross sections on it (lane width = 3.5 m and shoulder width = 1.5 m) 3#⁰
Intersection angle: 30
[40 pts] For the horizontal curve and the original cross-section of a two lane highway shown below, the following data is given: PI - Radius (R) = 15# m T T Intersection angle (A) = Design Speed (Va) = 60 km/h Stopping Sight Distance (S.) = 72.$$ m PC PT OE î Sr = 1/200 - f = 0.15 IE 2% 2% IE OE Find; a) Minimum lateral clearance distance (M.) b) Determine the maximum superelevation (emax) and transition length (L.) for rotation around centerline. c) Draw superelevation diagram by rotating the roadway around the center line and show all necessary cross sections on it (lane width = 3.5 m and shoulder width = 1.5 m) 3#⁰