p(wt) = N(w mN, SN) mN S N 1 SN (S¹mo +3¹t) T S¯¹ + ßÞ¹6. 0 (3.49) (3.50) (3.51) 3.7 (+) By using the technique of comp

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answerhappygod
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p(wt) = N(w mN, SN) mN S N 1 SN (S¹mo +3¹t) T S¯¹ + ßÞ¹6. 0 (3.49) (3.50) (3.51) 3.7 (+) By using the technique of comp

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P Wt N W Mn Sn Mn S N 1 Sn S Mo 3 T T S Ssth 6 0 3 49 3 50 3 51 3 7 By Using The Technique Of Comp 1
P Wt N W Mn Sn Mn S N 1 Sn S Mo 3 T T S Ssth 6 0 3 49 3 50 3 51 3 7 By Using The Technique Of Comp 1 (39.56 KiB) Viewed 40 times
P Wt N W Mn Sn Mn S N 1 Sn S Mo 3 T T S Ssth 6 0 3 49 3 50 3 51 3 7 By Using The Technique Of Comp 2
P Wt N W Mn Sn Mn S N 1 Sn S Mo 3 T T S Ssth 6 0 3 49 3 50 3 51 3 7 By Using The Technique Of Comp 2 (37.89 KiB) Viewed 40 times
p(wt) = N(w mN, SN) mN S N 1 SN (S¹mo +3¹t) T S¯¹ + ßÞ¹6. 0 (3.49) (3.50) (3.51)

3.7 (+) By using the technique of completing the square, verify the result (3.49) for the posterior distribution of the parameters w in the linear basis function model in which my and SN are defined by (3.50) and (3.51) respectively.
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