Pls explain with working, I don't understand the format that was
given to me....
Pls Explain With Working I Don T Understand The Format That Was Given To Me This Was The One That Was Sent To Me Vi 1 (53.15 KiB) Viewed 41 times
This was the one that was sent to me Via answers a few times when
i send the question. But i don't understand pls explain with
working.
Pls Explain With Working I Don T Understand The Format That Was Given To Me This Was The One That Was Sent To Me Vi 2 (85.2 KiB) Viewed 41 times
SECTION B (70 marks) Question 2 A conveyor belt is driven by a motor, via a compound gearbox and a belt drive. The gearbox has an efficiency of 90% and the speed reduction ratio 25:1. The belt drive has an efficiency of 96% and the speed reduction ratio 2:1. The conveyor drum requires a torque of 550 Nm at approximately 58 rpm. The belt conveyor operates for 12 hours per day and assume the load is gradually applied. Belt Drive 12 = 96%, VR2 = 2:1 Ø30 mm Conveyor Drum Motor 1 1000N Coupling Gearbox 1₁ = 90%, VR₁ = 25:1 Tension due to conveyor Drum Shaft Bearing A Belt Input shaft Figure 2.1 4 1 2 3 Fig.2A Layout of two-stage gearbox × Output shaft - D Bearing B 1500 N 1000 N IT p D B 50mm 150mm 150mm Fig.28 Layout of Dum Shaft
2.1 Motor (i) Calculate the rotational speed required by the motor. (ii) Calculate the power required by the motor. Select a suitable 3-phase Brook Crompton motor for the system stating the following: • Motor frame size: Motor power: Motor speed: Motor shaft diameter:
S: Given data 4 = 4m -A= 3900 mm" imm² € = 200 GPa - 200x 10³ HP From the Free Body Diagram & P-405 Taking moment about 1 ÷ By (2) - P(1) - P(1/2) = 0 By - P=0 By = P EFx-O -A+P=0 A₂ = -P Toints= {fy=0 Ay=0 By the Method off {Fx=0 -FAB+ FBC Cos45° = 0 FAB = FBC Co 45° €FA=0 By - FBC 8²1 45²=0 FBc Sin45 = By FBc = P4 = P√5 8in 45 FAB = FBC C0045° = P² (1₂) FAB = P
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