A Solution Containing 0 10 M Pb2 1 5 X 10 6 M Pb 15 10 M Mn 0 10 M Mno And 0 80 M Hno Was Prepared For This Solu 1 (29.7 KiB) Viewed 235 times
A Solution Containing 0 10 M Pb2 1 5 X 10 6 M Pb 15 10 M Mn 0 10 M Mno And 0 80 M Hno Was Prepared For This Solu 2 (20.81 KiB) Viewed 235 times
A Solution Containing 0 10 M Pb2 1 5 X 10 6 M Pb 15 10 M Mn 0 10 M Mno And 0 80 M Hno Was Prepared For This Solu 3 (13.93 KiB) Viewed 235 times
A solution containing 0.10 M Pb2+, 1.5 x 10-6 M Pb+. 15 10" M Mn,0.10 M Mno, and 0.80 M HNO, was prepared, For this solution, the balanced reduction half-reactions and overall net reaction shown can occur. 5[Pb++ + 20 = Pb2+1 E: = 1690 V 2 MnO, +8H+ +5 =Mn2+ + 4H,0 E' = 1.507 v 5 Pb++ + 2 Mn2+ + 8H,0 = 5 Pb2+ + 2 MnO + 16 H+ Determine E AG", and K for this reaction Ecell = AG = K-
Calculate the value for the cell potential, Ecelland the free energy. AG. for the given conditions. I Ecel = AG = Calculate the value of Ecell for this system at equilibrium. V Ece
Determine the pH at which the given concentrations of Pb2+ . Poft, Mn, and Mno, would be at equilibrium pH
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