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80 Ω b t = 0 a + 240 Ω Όρ. Copyright 2015 Pearson Education, All Rights Reserved + 100 V v(t) = [2755 + 160.08e-625t = 25 Ω www 100 Ω + 580 MF 275 V 16 mH cos(625t + 141.34°)]u(t) V
80 Ω b t = 0 a + 240 Ω Όρ. Copyright 2015 Pearson Education, All Rights Reserved + 100 V v(t) = [2755 + 160.08e-625t = 2
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80 Ω b t = 0 a + 240 Ω Όρ. Copyright 2015 Pearson Education, All Rights Reserved + 100 V v(t) = [2755 + 160.08e-625t = 2
answer shoudl be 275 not 2755 typo
80 Ω b t = 0 a + 240 Ω Όρ. Copyright 2015 Pearson Education, All Rights Reserved + 100 V v(t) = [2755 + 160.08e-625t = 25 Ω www 100 Ω + 580 MF 275 V 16 mH cos(625t + 141.34°)]u(t) V
80 Ω b t = 0 a + 240 Ω Όρ. Copyright 2015 Pearson Education, All Rights Reserved + 100 V v(t) = [2755 + 160.08e-625t = 25 Ω www 100 Ω + 580 MF 275 V 16 mH cos(625t + 141.34°)]u(t) V
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