(1 point) Use linear approximation to approximate 16.3 as follows. Let f(x)=√x. The equation of the tangent line to f(x)

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(1 point) Use linear approximation to approximate 16.3 as follows. Let f(x)=√x. The equation of the tangent line to f(x)

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1 Point Use Linear Approximation To Approximate 16 3 As Follows Let F X X The Equation Of The Tangent Line To F X 1
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1 Point Use Linear Approximation To Approximate 16 3 As Follows Let F X X The Equation Of The Tangent Line To F X 2
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1 Point Use Linear Approximation To Approximate 16 3 As Follows Let F X X The Equation Of The Tangent Line To F X 3
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(1 point) Use linear approximation to approximate 16.3 as follows. Let f(x)=√x. The equation of the tangent line to f(x) at x = 16 can be written in the form y = mx + b. Compute m and b. m == b= Using this find the approximation for √16.3. Answer:

(1 point) The line tangent to the graph of g(x) = x³-4x+1 at the point (2, 1) is given by the formula L(x) = 8(x-2) + 1. These functions are graphed below. -1 -18 10

-18 Which of the following statements are true? Select all that apply. A. The functions are approximately equal on the interval 0.5 ≤ x ≤ 1.0. B. The graphs intersect at the point (2, 1). C. The functions have the same y-intercept. D. The functions are approximately equal on the interval 1.9 ≤ x ≤ 2.1. E. The slope of the line equals g' (2). F. The slope of the line equals g' (0). G. None of the above are true.
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