- A Rock Thrown Vertically Upward From The Surface Of The Moon At A Velocity Of 8 M Sec Reaches A Height Of S 8t 0 8t Me 1 (45.09 KiB) Viewed 55 times
A rock thrown vertically upward from the surface of the moon at a velocity of 8 m/sec reaches a height of s= 8t-0.8t² me
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A rock thrown vertically upward from the surface of the moon at a velocity of 8 m/sec reaches a height of s= 8t-0.8t² me
A rock thrown vertically upward from the surface of the moon at a velocity of 8 m/sec reaches a height of s= 8t-0.8t² meters in t sec. a. Find the rock's velocity and acceleration at time t b. How long does it take the rock to reach its highest point? c. How high does the rock go? d. How long does it take the rock to reach half its maximum height? e. How long is the rock aloft? a. Find the rock's velocity at time t. v=m/s Find the rock's acceleration at time t. a = m/s² (Simplify your answer. Use integers or decimals for any numbers in the expression.) b. How long does it take the rock to reach highest point? sec (Simplify your answer.) c. How high does the rock go? (Simplify your answer.) d. How long does it take the rock to reach half its maximum height? sec (Simplify your answer. Round to two decimal places as needed. Use a comma to separate answers as needed.) e. How long is the rock aloft?