y" + y² = 2 + 2x + x² y (0) = 8, y '(0) = -1 1
Posted: Tue Jun 07, 2022 6:57 am
- Y Y 2 2x X Y 0 8 Y 0 1 1 1 (51.61 KiB) Viewed 30 times
y" + y² = 2 + 2x + x² y (0) = 8, y '(0) = -1 1
The final answer is c1 + c2 e^-x + x^3/3 + 2x
y" + y² = 2 + 2x + x² y (0) = 8, y '(0) = -1 1