y" + y² = 2 + 2x + x² y (0) = 8, y '(0) = -1 1

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answerhappygod
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y" + y² = 2 + 2x + x² y (0) = 8, y '(0) = -1 1

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Y Y 2 2x X Y 0 8 Y 0 1 1 1
Y Y 2 2x X Y 0 8 Y 0 1 1 1 (51.61 KiB) Viewed 29 times
The final answer is c1 + c2 e^-x + x^3/3 + 2x
y" + y² = 2 + 2x + x² y (0) = 8, y '(0) = -1 1
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