5. Evaluate by interpreting it in terms of areas. ♫ √√16-x² dx 0 [22] = [Eve]+ = [[[2]ng # + *] 428 Any √√√16-2² dx = 2
Posted: Tue Jun 07, 2022 5:37 am
- 5 Evaluate By Interpreting It In Terms Of Areas 16 X Dx 0 22 Eve 2 Ng 428 Any 16 2 Dx 2 1 (13.2 KiB) Viewed 46 times
- 5 Evaluate By Interpreting It In Terms Of Areas 16 X Dx 0 22 Eve 2 Ng 428 Any 16 2 Dx 2 2 (9.47 KiB) Viewed 46 times
0 [22] = [Eve]+ = [[[2]ng # + *] 428 Any √√√16-2² dx = 2, 2√√√²-x² dx