5. Evaluate by interpreting it in terms of areas. ♫ √√16-x² dx 0 [22] = [Eve]+ = [[[2]ng # + *] 428 Any √√√16-2² dx = 2

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answerhappygod
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5. Evaluate by interpreting it in terms of areas. ♫ √√16-x² dx 0 [22] = [Eve]+ = [[[2]ng # + *] 428 Any √√√16-2² dx = 2

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5 Evaluate By Interpreting It In Terms Of Areas 16 X Dx 0 22 Eve 2 Ng 428 Any 16 2 Dx 2 1
5 Evaluate By Interpreting It In Terms Of Areas 16 X Dx 0 22 Eve 2 Ng 428 Any 16 2 Dx 2 1 (13.2 KiB) Viewed 44 times
5 Evaluate By Interpreting It In Terms Of Areas 16 X Dx 0 22 Eve 2 Ng 428 Any 16 2 Dx 2 2
5 Evaluate By Interpreting It In Terms Of Areas 16 X Dx 0 22 Eve 2 Ng 428 Any 16 2 Dx 2 2 (9.47 KiB) Viewed 44 times
5. Evaluate by interpreting it in terms of areas. ♫ √√16-x² dx

0 [22] = [Eve]+ = [[[2]ng # + *] 428 Any √√√16-2² dx = 2, 2√√√²-x² dx
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