SO42- + 8e- + 9H+ --> HS- + 4H2O

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answerhappygod
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SO42- + 8e- + 9H+ --> HS- + 4H2O

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SO42- + 8e- + 9H+ --> HS- + 4H2O
Say that a wetland has been contaminated with 21.4 kg of toluene (C7H8). Using the balanced reduction half reaction from question #3, What mass of SO42- (in kg) will be needed to oxidize all the toluene to CO2? To solve this, first balance this oxidation half reaction. _H2O + _C7H8 --> _CO2 + H+ + Then determine the overall redox reaction. Then it is a stoichiometry problem. Show work
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