- Pyhton Code Block A Fill The Code For Line 2 And On Code Block B Given A List Of Numbers Find And Print The Elements Th 1 (44.2 KiB) Viewed 80 times
- Pyhton Code Block A Fill The Code For Line 2 And On Code Block B Given A List Of Numbers Find And Print The Elements Th 2 (33.97 KiB) Viewed 80 times
code block B
Given a list of numbers, find and print the elements that appear in it only once. Such elements should be printed in the order in which they occur in the original list. You must use list comprehension.
Same input output as code block 1
- Pyhton Code Block A Fill The Code For Line 2 And On Code Block B Given A List Of Numbers Find And Print The Elements Th 3 (65.88 KiB) Viewed 80 times
Please help me with code block A & B, I really need help Please!!!
Problem Statement: Given a list of numbers, find and print the elements that appear in it only once. Such elements should be printed in the order in which they occur in the original list. Criteria: Test # Input Output 43525135 421 122333 1 6 9 6 23 12 19 14 26 9 23 12 19 14 26 21 21 16 20 28 28 7 16 20 7 21 21 5 2 29 4 28 8 5 2 29 4 28 8 429329784 378 |1 2 3 14 15
unique_elements.py 1 def get_unique_elements (a_list): 2 a list [int (str_numbers) for str_numbers in input ().split() ] # Input list creation via list comprehensi 5 print (*get unique elements (a list)) 2345
unique_elements_list_compre.py 1 # Please replace . . . (three dots) with your code. Don't forget the indentation. 2 def get_unique_elements (a_list): # a_list here is called formal parameter | | | 3 'Returns a list of unique elements of a list''' # Return your comprehension below 7 test cases = [[4, 3, 5, 2, 5, 1, 3, 5], [1, 2, 2, 3, 3, 3], [6, 9, 6, 23, 12, 19, 14, 26], [21, 21, 16, 20, for lists in test_cases: print (*get_unique_elements (lists)) 234 4 5 56789