-31110 = 144.15 J 2. A 26.05 g sample of samarium, initially at 99.6°C, was added to 50.0 g of distilled water (initiall

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answerhappygod
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-31110 = 144.15 J 2. A 26.05 g sample of samarium, initially at 99.6°C, was added to 50.0 g of distilled water (initiall

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31110 144 15 J 2 A 26 05 G Sample Of Samarium Initially At 99 6 C Was Added To 50 0 G Of Distilled Water Initiall 1
31110 144 15 J 2 A 26 05 G Sample Of Samarium Initially At 99 6 C Was Added To 50 0 G Of Distilled Water Initiall 1 (27.37 KiB) Viewed 128 times
-31110 = 144.15 J 2. A 26.05 g sample of samarium, initially at 99.6°C, was added to 50.0 g of distilled water (initially at 26.83°C) in a Styrofoam cup. The final temperature of the water and the metal was 28.40°C. Calculate the specific heat of samarium.
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