B. VOLTAIC CELL then i wery moral is mg Cell Voltage, mV Mg - Cu +6.78 1678 Mg - Za 650 27 1. Write the half-cell reacti

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B. VOLTAIC CELL then i wery moral is mg Cell Voltage, mV Mg - Cu +6.78 1678 Mg - Za 650 27 1. Write the half-cell reacti

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B Voltaic Cell Then I Wery Moral Is Mg Cell Voltage Mv Mg Cu 6 78 1678 Mg Za 650 27 1 Write The Half Cell Reacti 1
B Voltaic Cell Then I Wery Moral Is Mg Cell Voltage Mv Mg Cu 6 78 1678 Mg Za 650 27 1 Write The Half Cell Reacti 1 (23.78 KiB) Viewed 47 times
B Voltaic Cell Then I Wery Moral Is Mg Cell Voltage Mv Mg Cu 6 78 1678 Mg Za 650 27 1 Write The Half Cell Reacti 2
B Voltaic Cell Then I Wery Moral Is Mg Cell Voltage Mv Mg Cu 6 78 1678 Mg Za 650 27 1 Write The Half Cell Reacti 2 (19.24 KiB) Viewed 47 times
B Voltaic Cell Then I Wery Moral Is Mg Cell Voltage Mv Mg Cu 6 78 1678 Mg Za 650 27 1 Write The Half Cell Reacti 3
B Voltaic Cell Then I Wery Moral Is Mg Cell Voltage Mv Mg Cu 6 78 1678 Mg Za 650 27 1 Write The Half Cell Reacti 3 (19.76 KiB) Viewed 47 times
B. VOLTAIC CELL then i wery moral is mg Cell Voltage, mV Mg - Cu +6.78 1678 Mg - Za 650 27 1. Write the half-cell reactions and calculate the standard cell potential, for the Mg-Cu voltaic cell. Oxidation half-cell Reduction half-cell Cu2+ + 2e Cu E = +0.340U to = -2.356 V Чg ? Mg 2 +2e 27 Complete equation Standard cell potential, E, Mg + Cu2+ Mg 2+ + Cu — + + 2.7097 to cell = +2.372+0.337=/+ 2.709 /

2. Write the half-cell reactions and calculate the standard cell potential, E for the Mg-Zn voltaic cell. E- Oxidation half-cell an + ze 7 in Reduction half-cell to = -0.76 V Mg, 7 Mg 2+ the — 2.356 V 2- Zn? + Complete equation Standard cell potential, E Mg → Zn + Mg 2+ 1.596 V - 2.3 56v - (-0.760) = -1.5960 Tell

Table 29.1 Standard Reduction Potentials for Select Metals +2e- E E +0.340V red = -0.136V = -0.257V Ted E Cu?" (aq) → Cu(s) Sn?" (aq) + 2e- → Sn(s) Ni?"(aq) + 2e- Ni(s) Zn(aq) + 2e- Zn(s) A13(aq) + 3e- → Als) Mg?"(aq) + 2e- + 2e- — Mg(s) red E = -0.763V red E = -1.706V red E = -2.356V red
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