Given:
Balanced chemical equation = (attached)
Raw materials = 2 kg sodium borate and 1 kg hydrochloric acid
Actual Yield = 1.221 kgs boric acid
Formulation = 0.004 mg per 50 microliter drop
Dosage Form = Ophthalmic solution
Packaging = 15 mL plastic drip bottles
Solve for the following:
A. Perecent(%) Composition by mass of each compound in the balanced chemical equation
B. Mass to mass stoichiometry calculation
C. Limiting reagent
D. Excess Reagent
E. Amount (g) in excess
F. Percent Yield
F. Number of dosage form and packaging that can be produced from stoichiometric calculation
Given:
Balanced chemical equation = (attached)
Raw materials = 2 kg sodium borate and 1 kg hydrochloric acid
Actual Yield = 1.221 kgs boric acid
Formulation = 0.004 mg per 50 microliter drop
Dosage Form = Ophthalmic solution
Packaging = 15 mL plastic drip bottles
Solve for the following:
A. % Composition by mass of each compound in the balanced chemical equation
B. Mass to mass stoichiometry calculation
C. Limiting reagent
D. Excess Reagent
E. Amount (g) in excess
F. Percent Yield
F. Number of dosage form and packaging that can be produced from stoichiometric calculation
Given: Balanced chemical equation = (attached) Raw materials = 2 kg sodium borate and 1 kg hydrochloric acid Actual Yiel
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