A ball is thrown downward with a speed of 12 ft/s from the top of a 144-foot-tall building. After t seconds, its height

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A Ball Is Thrown Downward With A Speed Of 12 Ft S From The Top Of A 144 Foot Tall Building After T Seconds Its Height 1 (69.72 KiB) Viewed 34 times

A ball is thrown downward with a speed of 12 ft/s from the top of a 144-foot-tall building. After t seconds, its height above the ground is given by s(t) = -24t² - 12t+144. (a) Determine how long it takes for the ball to hit the ground. sec (b) Determine the velocity of the ball when it hits the ground. ft/sec If s(t) = 8t³ 12t² - 48t + 7, where t≥ 0 represent the position of a particle traveling along a horizontal line. Determine the time intervals when the object is slowing down or speeding up from the velocity and acceleration functions. O speeding up in O speeding up in O speeding up in O speeding up in O speeding up in (0,0.5) U (2, 7)and slowing down in (0.5, 2) (0,0.5) U (2, ∞) and slowing down in (7,00) (0,0.5) U (2, ∞o)and slowing down in (0.5, 00) (0,0.5) n (2, ∞)and slowing down in (0.5, 2) (0,0.5) U (2, ∞o) and slowing down in (0.5, 2)