- The Sketch Following Shows The Traverse From A To B Along The Horizontal Alignment Of A Rural Highway A Circular Curve 1 (48.08 KiB) Viewed 32 times
The sketch following shows the traverse from A to B, along the horizontal alignment of a rural highway. A circular curve
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The sketch following shows the traverse from A to B, along the horizontal alignment of a rural highway. A circular curve
The sketch following shows the traverse from A to B, along the horizontal alignment of a rural highway. A circular curve joins the points BC and EC. The Y and X coordinates of points A, PI and B are given in the table below. Assume point A is situated at chainage 0+000. PI EC BC Beginning of the circular curve End of the circular curve. A - Central angle Sketch not to scale Formula Point Y (m) Radius (m) X (m) +25271.315 TRA A -16155.234 0 L= 180 PI -18572.006 +24003.839 300 T = Rtan () -23132.364 B 0 +26215.211 2.1 Do join calculations and determine the central angle (A). 2.2 Calculate the circular curve length (L) and the tangent length (T). 2.3 Compute the chainages of BC, EC, and the mid-point on the curve (MP). 2.4 Do polar calculations and determine the coordinates of BC. BC EC (22) (4) (6) (8) [40 marks]