**For the circuit in Fig. 4 answer (11, 12 and 13) 11) the voltage Vift) can be expressed as: a) sin( wr+45) c) 2 sin(wr

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answerhappygod
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**For the circuit in Fig. 4 answer (11, 12 and 13) 11) the voltage Vift) can be expressed as: a) sin( wr+45) c) 2 sin(wr

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For The Circuit In Fig 4 Answer 11 12 And 13 11 The Voltage Vift Can Be Expressed As A Sin Wr 45 C 2 Sin Wr 1
For The Circuit In Fig 4 Answer 11 12 And 13 11 The Voltage Vift Can Be Expressed As A Sin Wr 45 C 2 Sin Wr 1 (45.44 KiB) Viewed 32 times
**For the circuit in Fig. 4 answer (11, 12 and 13) 11) the voltage Vift) can be expressed as: a) sin( wr+45) c) 2 sin(wr+60") d) cos(wt-45) e) cos(wt+45) 195 f) sin(wt-60) d) I e) 5m c) 90° answer ( 14, 15, and 16) f) none D) 2 E) 5 12) the frequency of wave (t) in rad's is: a) 2x b) 0.8 c) 1.25 13) V.(t) lags Vi(t) by:a)-110" b) 60" c) -90° d) -60° *For the circuit in Fig. 5 use superposition to find the current 14) I, due to only 6v source in (A) is: A)1 B) 3 C)-0.25 15) I, due to only 4 A source in (A) is: A)-1 B) 5 C)6 16) I, due to only 2A source in (A) is: A) 0.25 B) 3.5 C) 3 D)-0.5 17) Use the color code table. The expected value of a resistor with color code (red violet orange) is: A) 27k B) 3.5K C) 1.5K D) 22K E) 2K F) None D)2 E) 1 E) 2 Digit Color 0 Black Brown 2 Red Orange Yellow 18) A sine wave with a period of 2 ms is changing at a faster rate than a sine wave with a period of: A) Ims B) 0.0025 s C) 1.5 ms D) 0.5 m E) 100μs F) None 5 Green 6 Blue 7 Violet Gray 19) The minimum and maximum resistance for SK2 with a tolerance of 20% in 2 are: a) 4.5k, 6.5kb) 2k, 6k c) 4k, 6k d) 990, 1100 c) 3k, 7k f) none White 20) While checking out a series resistive circuit, you find that the current is higher than it should be. You should look for: A) an open circuit C) a low resistor value D) a high resistor value F) both choices (B & C) B) a short E) both choices (A & D) fig.4 fig.5 2 A va(t) www MA 202 Al 692 4A 402 B PA3 92 04 vb(t) t(s) b) 2 sin(wt-45) 6V F) 0.7 G) None F)3 G) None F)-2 G) None 305 1
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