to sin(n)u[n] Z (b) X2 (2) = 22 +1 84. Use Modulation and the z-Transform pair u[n]→→→→→ cos(n)u[n]→→→→→→ z²-zcos(22) 2²

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answerhappygod
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to sin(n)u[n] Z (b) X2 (2) = 22 +1 84. Use Modulation and the z-Transform pair u[n]→→→→→ cos(n)u[n]→→→→→→ z²-zcos(22) 2²

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To Sin N U N Z B X2 2 22 1 84 Use Modulation And The Z Transform Pair U N Cos N U N Z Zcos 22 2 1
To Sin N U N Z B X2 2 22 1 84 Use Modulation And The Z Transform Pair U N Cos N U N Z Zcos 22 2 1 (15.79 KiB) Viewed 32 times
Here is the answer. Could you please show the whole process
To Sin N U N Z B X2 2 22 1 84 Use Modulation And The Z Transform Pair U N Cos N U N Z Zcos 22 2 2
To Sin N U N Z B X2 2 22 1 84 Use Modulation And The Z Transform Pair U N Cos N U N Z Zcos 22 2 2 (3.58 KiB) Viewed 32 times
To Sin N U N Z B X2 2 22 1 84 Use Modulation And The Z Transform Pair U N Cos N U N Z Zcos 22 2 3
To Sin N U N Z B X2 2 22 1 84 Use Modulation And The Z Transform Pair U N Cos N U N Z Zcos 22 2 3 (3.22 KiB) Viewed 32 times
to sin(n)u[n] Z (b) X2 (2) = 22 +1 84. Use Modulation and the z-Transform pair u[n]→→→→→ cos(n)u[n]→→→→→→ z²-zcos(22) 2²-2z cos(22) +1 Hence find the inverse z-transforms of (a) X₁ (z) = derive the z-Transform pairs zsin(2) 2²-2zcos (2) +1
84. (a) x₁ [n] = cos(лn/2)u[n]
(b) x₂ [n] = sin(tn/2)u[n]
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