Consider "textbook" RSA: N is the public modulus, e is the public exponent, d is the private exponent. Encryption of a m

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Consider Textbook Rsa N Is The Public Modulus E Is The Public Exponent D Is The Private Exponent Encryption Of A M 1 (53.33 KiB) Viewed 11 times

Consider "textbook" RSA: N is the public modulus, e is the public exponent, d is the private exponent. Encryption of a message m is computed by taking Enc(m) = m^e mod N 1. Why is this scheme not secure in the perfect secrecy sense? How could an adversary find out the message if the corresponding ciphertext is given? 2. Why is this scheme in itself not secure in the computational sense either? 3. What is usually applied to the message in practice before encryption? 4. What do we expect for the usability of RSA in the longer term? Why? HTML Editor