Heat of Neutralization Data and Results Original temp of HCl solution 22.0c Original temp of NaOH solution 22 6C Final t

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Heat Of Neutralization Data And Results Original Temp Of Hcl Solution 22 0c Original Temp Of Naoh Solution 22 6c Final T 1 (35.97 KiB) Viewed 70 times

-h per mole

Heat Of Neutralization Data And Results Original Temp Of Hcl Solution 22 0c Original Temp Of Naoh Solution 22 6c Final T 2 (35.97 KiB) Viewed 70 times

Heat Of Neutralization Data And Results Original Temp Of Hcl Solution 22 0c Original Temp Of Naoh Solution 22 6c Final T 3 (35.97 KiB) Viewed 70 times

Heat Of Neutralization Data And Results Original Temp Of Hcl Solution 22 0c Original Temp Of Naoh Solution 22 6c Final T 4 (47.69 KiB) Viewed 70 times

Heat Of Neutralization Data And Results Original Temp Of Hcl Solution 22 0c Original Temp Of Naoh Solution 22 6c Final T 5 (22.93 KiB) Viewed 70 times

Heat Of Neutralization Data And Results Original Temp Of Hcl Solution 22 0c Original Temp Of Naoh Solution 22 6c Final T 6 (34.33 KiB) Viewed 70 times

Heat of Neutralization Data and Results Original temp of HCl solution 22.0c Original temp of NaOH solution 22 6C Final temp of neutralized mixture 35.3C Change in temp (use average original temp of 26.6C HCl and NaOH) QH20 for the reaction (get mass using 50 0 2774J ml solution and d= 1.02 g/mL) AH for the reaction (eqn 4) -27743 AH per mole kJ/mol

Data/ Calculations Specific Heat Data and Results Mass of calorimeter 17.00g 56.159 39.15g Mass of calorimeter and water Mass of water Mass of metal Initial temperature of water in calorimeter Initial temperature of metal Equilibrium temperature of water and metal Atwater(tfinal - tinitial) 57.619 21.9C 273C 5.4C 16.5C Atmeta -21.90 2700 170 он20 Specific heat of the metal (egn 3) Unknown 17168.J/g oC 89

Preaction = AH reaction = -9H20 (eqn 4) NaOH(s) - Na*(aq) + OH(aq); AH = AH solution (eqn 5) Solution with o int H'(am + OH(aq) - HO (O); AH = Anetration (en 6)

or una substance. a = Cs xm At (eqn 1) 4H20 = -metal (eqn2) now express heat flow in terms of Equation 1 for both the water and the metal, we get (Equation 3): 9= C3,H20 X MH20 * Ath2o = - Cs metal * Mmetat * Atmetat (eqn 3)