- Effectiveness E Time Left 0 31 Shell Fluid 4a Shell Fluid L L 1 1 2 3 4 5 1 2 3 4 5 Number Of Transfer Units Ntu A 1 (364.71 KiB) Viewed 11 times
Effectiveness E, % Ⓒ Time left 0:31 Shell fluid 4A Shell fluid L L 1 1 2 3 4 5 1 2 3 4 5 Number of transfer units NTU=A,
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Effectiveness E, % Ⓒ Time left 0:31 Shell fluid 4A Shell fluid L L 1 1 2 3 4 5 1 2 3 4 5 Number of transfer units NTU=A,
Effectiveness E, % Ⓒ Time left 0:31 Shell fluid 4A Shell fluid L L 1 1 2 3 4 5 1 2 3 4 5 Number of transfer units NTU=A,U/C min Number of transfer units NTU=A,U/C min [20] a) Calculate the effectiveness of the parallel flow double pipe heat exchanger shown above. (Water thermal properties could be assumed as constant.) [20] b) What would have been the outlet temperatures of the cold and hot water streams if the exchanger would be twice as long ? [20] c) Would you be able to increase the heat transfer rate between the fluids if you would reverse the cold water flow direction on the outer tube ? If yes, please quantify the heat transfer rate rise. If not, briefly explain your reasoning. 100 80 60 40 20 0 0.5 kg/s 90 deg C đô Cmin max. 0.25 0.50 0.75 1.00 Tube fluid 10 deg C 1 kg/s Effectiveness , % 100 80 60 40 20 15 deg C 0 Cmin max IC 0.75 0.50 0.25 1.00 Tube fluid 0