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Please do not use previous answers, as the other ones that are published are wrong.

Posted: Wed May 25, 2022 7:35 am
by answerhappygod
Please do not use previous answers, as the other ones that are
published are wrong.
Please Do Not Use Previous Answers As The Other Ones That Are Published Are Wrong 1
Please Do Not Use Previous Answers As The Other Ones That Are Published Are Wrong 1 (25.05 KiB) Viewed 17 times
A very general expression for the Hamiltonian of a particle in one dimension is 2 p² = + V(Â). 2m = By calculating [[Ĥ, X], X], or otherwise, prove that Σ;|(a;|×|a;)|²(E; — E;) = energy eigenket corresponding to eigenvalue E₁. " 2m where la;) is the