published are wrong.
- Please Do Not Use Previous Answers As The Other Ones That Are Published Are Wrong 1 (25.05 KiB) Viewed 15 times
Please do not use previous answers, as the other ones that are published are wrong.
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answerhappygod
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Please do not use previous answers, as the other ones that are published are wrong.
Please do not use previous answers, as the other ones that are
published are wrong.
A very general expression for the Hamiltonian of a particle in one dimension is 2 p² = + V(Â). 2m = By calculating [[Ĥ, X], X], or otherwise, prove that Σ;|(a;|×|a;)|²(E; — E;) = energy eigenket corresponding to eigenvalue E₁. " 2m where la;) is the
published are wrong.
A very general expression for the Hamiltonian of a particle in one dimension is 2 p² = + V(Â). 2m = By calculating [[Ĥ, X], X], or otherwise, prove that Σ;|(a;|×|a;)|²(E; — E;) = energy eigenket corresponding to eigenvalue E₁. " 2m where la;) is the